16x^2+46x-28=0

Solution for 16x^2+46x-28=0 equation:

16x^2+46x-28=0

a = 16; b = 46; c = -28;
Δ = b2-4ac
Δ = 462-4·16·(-28)
Δ = 3908
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3908}=\sqrt{4*977}=\sqrt{4}*\sqrt{977}=2\sqrt{977}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(46)-2\sqrt{977}}{2*16}=\frac{-46-2\sqrt{977}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(46)+2\sqrt{977}}{2*16}=\frac{-46+2\sqrt{977}}{32}
$